14x^2+3.14=13x^2+10(3.14)

Solution for 14x^2+3.14=13x^2+10(3.14) equation:

14x^2+3.14=13x^2+10(3.14)

We move all terms to the left:

14x^2+3.14-(13x^2+10(3.14))=0


We calculate terms in parentheses: -(13x^2+10(3.14)), so:

13x^2+10(3.14)

We add all the numbers together, and all the variables

13x^2+31.4

Back to the equation:

-(13x^2+31.4)


We get rid of parentheses

14x^2-13x^2-31.4+3.14=0

We add all the numbers together, and all the variables

x^2-28.26=0

a = 1; b = 0; c = -28.26;
Δ = b2-4ac
Δ = 02-4·1·(-28.26)
Δ = 113.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{113.04}}{2*1}=\frac{0-\sqrt{113.04}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{113.04}}{2*1}=\frac{0+\sqrt{113.04}}{2}
=\frac{\sqrt{}}{2}
$